Problem: Consider one way of modeling a problem. Say you have a device and in any given year, there is a 1 in 6 chance that the device will fail. One question is, “On average, how long will it be before such a device fails?” This sort of problem is what will be modeled and analyzed here.
The problem above can be modeled as follows: Roll a normal fair six-sided die. Rolling a 1 will count as “fail”. Anything else will count as “not-fail”. The random variable we will use will be
= # of rolls required until a 1 is rolled = “time until failure”
This is a random variable, so in each experiment (for each device), this will produce a value. For example, if we roll , then = 5 (we count the final roll).
Part 1 [Excel] (Empirical Analysis): Simulate 20 repetitions of obtaining a value for , that is, roll until a 1 is rolled, record the result and repeat this 20 times. For example, if you roll , then record 4 since 4 rolls were required. You can complete this using a die or simulating using Excel, Python, or some other option,
Excel might be used for this part as it makes the calculations, recording of data, etc. very simple. However, it is not required.
Part 2 [Excel] (Theoretical Analysis – Approximations): Compute approximations to expected value, variance, and standard deviation of the random variable . See the additional notes for discussion on these computations, in brief:
Use this table to compute
Again, using Excel for this will simplify what needs to be done.
Part 3 [Written] (Theoretical Analysis – Exact Computations – (Optional)): Compute the expected value, variance, and standard deviation of the random variable . See the additional notes for discussion on these computations, in brief:
Hint: For computing these without directly manipulating the infinite summations that appear in the definitions of and , let be the event that a 1 is rolled on the first throw and be the complementary event, namely, that a 1 is not rolled on the first throw. It is clear that since what is rolled after the first roll is just like starting over. It is also clear that . The Law of Total Expectation (see notes) gives:
This makes it quite simple to find .
A similar “trick” can be used to find , here you will use . Again, the Law of Total Expectation gives:
and from this it is simple to compute .